1. Ashok's age is (1/6) th of his father's age. The father's age will be twice of Kamal's age after 10 years. If Kamal's eighth birthday was celebrated 2 years before, what is Ashok's present age?
(a) 24 years
(b) 30 years
(c) 6(2/3) years
(d) None of these
(e) Cannot be determined
Sol.
1. (d); Kamal's present age=10 years
Kamal's age after 10 years=20 years
Father's age after 10 years =40 years
Father's age now=30 years
Ashok's age now=[(1/6)X30]years=5 years
2. The sum of the ages of a father and son is 45 years. Five years ago the product of their ages was 4 times the father's age at that time. The present ages of the father and son respectively are:
(a) 25 years, 10 years
(b) 36 years, 9 years
(c) 39 years, 6 years
(d) None of these
(e) Cannot be determined
Sol.
2. (b); Let son's age=x. Then, father's age=(45-x)
(x-5) (45-x-5)=4(45-x-5)
x-5=4
x=9
Therefore, Father's age now=36 years & son's age=9 years.
3. 10 years ago, Mona's mother was 4 times older than her daughter. After 10 years, the mother will be twice older than the daughter. Mona's present age is:
(a) 5 years
(b) 10 years
(c) 20 years
(d) 30 years
(e) None of these
Sol.
3. (c); Let Mona's age 10 yrs ago=x. Her mother's age then=4x.
2(x+20)=4x+20
2x=20
x=10
Therefore, Mona's present age=(10+10)years=20 years
4. Three years ago, the average age of A and B was 18 years. With C joining them, the average becomes 22 years. How old is C now?
(a) 24 years
(b) 27 years
(c) 28 years
(d) 30 years
(e) None of these
Sol.
4. (a); (A+B)'s age 3 years ago=(18X2)=36 years
(A+B) now=(36+3X2)years=42 years.
(A+B+C) now=(3X22) years=66 years.
C's present age=(66-42) years=24 years.
5. Kamla got married 6 years ago. Today her age is 1(1/4) times her age at the time of marriage. He son's age is 1/10 times her age. Her son's age is:
(a) 2 years
(b) 3 years
(c) 4 years
(d) 5 years
(e) None of these
Sol.
5. (b); Let Kamla's age 6 years ago be x.
therefore, (x+6)=(5/4)x
4(x+6)=5x
x=24
therefore, Kamla's present age=30 years.
therefore, Kamla's son's present age=[(1/10)X30] years=3 years
6. One year ago the ratio of Varun and Veena's ages was 4 : 5. One year hence the ratio of their ages will be 5 : 6. The present age of Veena is:
(a) 9 years
(b) 10 years
(c) 12 years
(d) 6 years
(e) None of these
Sol.
6. (c); Let their ages 1 years ago be 4x and 5x.
[(4x+2)/(5x+2)]=5/6
6(4x+2)=5(5x+2)
x=2
therefore, Veena's present age=(5x+2)=12 years.
7. A is as much younger to B as he is older to C. If the sum of the ages of B and C is 48 years, what is the present age of A?
(a) 20 years
(b) 24 years
(c) 30 years
(d) 36 years
(e) None of these
Sol.
7. (b); B-A=A-C
2A=B+C
2A=48
A=24
8. Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what is the sum of their present ages?
(a) 8 years
(b) 20 years
(c) 35 years
(d) 45 years
(e) None of these
Sol.
8. (c); Let their present ages be 3x and 4x. Then,
2(3x-10)=4x-10
2x=10
x=5
therefore, Sum of their present ages=7x=35 years.
9. The ratio of Laxmi's age to the age of her mother is 3 : 11. The difference of their ages is 24 years. The ratio of their ages after 3 years will be:
(a) 1 : 3
(b) 2 : 3
(c) 3 : 5
(d) 2 : 5
(e) None of these
Sol.
9. (a); Let their ages be 3x & 11x.
11x-3x=24
x=3
Their present ages are 9 years & 33 years.
Ratio of their ages after 3 years = 12 : 36 =1 : 3
10. The age of a man is 4 times that of his son. Five years ago, the man was nine times as old as his sone was at that time. The present age of the man is:
(a) 28 years
(b) 32 years
(c) 40 years
(d) 44 years
(e) None of these
Sol.
10. (b); Let the son's age be x. Then, father's age=4x.
therefore, (4x-5)=9(x-5)
5x=40
x=8
therefore, Present age of the man=32 years.
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