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1. A passenger train takes two hours less for a journey of 300km if its speed is increased by 5km/hr from its normal speed. The normal speed is:
A.35 km/hr
B.50 km/hr
C.25 km/hr
D.30 km/hr
E. 37Km/hr


2. A thief steals a car and drives it at 15 km/hr. The theft has been discovered after one hour and the owner of the car sets off in another car at 25 km/hr. When will the owner overtake the thief from the starting point?
A.1 hr
B.1.5 hr
C.2 hr
D.2.5 hr
E. 3 hr

3.A car travels first half distance between two places with a speed of 40 km/hr and rest of the half distance with a speed of 60 km/hr. The average speed of the car is:
A.48 km/hr
B.37 km/hr
C.44 km/hr
D.45 km/hr
E. 42 Km/hr

4.Two identical trains A and B running in opposite direction at same speed tale 2 min to cross each other completely. The number of bogies of A are increased from 12 to 16. How much more time would they now require to cross each other?
A.40 sec
B.50 sec
C.60 sec
D.20 sec
E. 30 sec

5.The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
A. 123
B. 127
C. 235
D.  305
E.  302

6.If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:
A. 55/601
B. 601/55
C. 11/120
D. 120/11
E. 110/12

7.Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?
A. 4
B. 10
C. 15
D. 16
E. 14

8. A sum of money lent at compound interest for 2 years at 20% per annum would fetch Rs.482 more, if the interest was payable half yearly than if it was payable annually . The sum is
A. 10000
B.  20000
C. 40000
D. 50000

9.A sum of money amounts to Rs.6690 after 3 years and to Rs.10,035 after 6 years on compound interest.find the sum.
A. 4360
B.  4460
C.  4560
D.  4660

10.The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is:
A. 3
B. 4
C. 5
D. 6

Answers

1.(C)
Let the normal speed be 's' km/hr
Then new speed =(s+5) km/hr
300/s-2 =300/(s+5)
On solving this equation
s = 25 km/hr

2. (B)
3. (A)
4. (A)
5. (B)


6. (C)
Let the numbers be a and b.
Then, a + b = 55 and ab = 5 x 120 = 600.
The required sum = (1/a)+(1/b) = (a+b)/ab = 55/600 = 11/120

7.(D)
L.C.M. of 2, 4, 6, 8, 10, 12 is 120.
So, the bells will toll together after every 120 seconds(2 minutes).
In 30 minutes,they will together (30/2)+1=16 times

8.(B)
9.(B)
10.(B)

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